x^2+3x+21=4x^2+12x+27

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Solution for x^2+3x+21=4x^2+12x+27 equation:


Simplifying
x2 + 3x + 21 = 4x2 + 12x + 27

Reorder the terms:
21 + 3x + x2 = 4x2 + 12x + 27

Reorder the terms:
21 + 3x + x2 = 27 + 12x + 4x2

Solving
21 + 3x + x2 = 27 + 12x + 4x2

Solving for variable 'x'.

Reorder the terms:
21 + -27 + 3x + -12x + x2 + -4x2 = 27 + 12x + 4x2 + -27 + -12x + -4x2

Combine like terms: 21 + -27 = -6
-6 + 3x + -12x + x2 + -4x2 = 27 + 12x + 4x2 + -27 + -12x + -4x2

Combine like terms: 3x + -12x = -9x
-6 + -9x + x2 + -4x2 = 27 + 12x + 4x2 + -27 + -12x + -4x2

Combine like terms: x2 + -4x2 = -3x2
-6 + -9x + -3x2 = 27 + 12x + 4x2 + -27 + -12x + -4x2

Reorder the terms:
-6 + -9x + -3x2 = 27 + -27 + 12x + -12x + 4x2 + -4x2

Combine like terms: 27 + -27 = 0
-6 + -9x + -3x2 = 0 + 12x + -12x + 4x2 + -4x2
-6 + -9x + -3x2 = 12x + -12x + 4x2 + -4x2

Combine like terms: 12x + -12x = 0
-6 + -9x + -3x2 = 0 + 4x2 + -4x2
-6 + -9x + -3x2 = 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
-6 + -9x + -3x2 = 0

Factor out the Greatest Common Factor (GCF), '-3'.
-3(2 + 3x + x2) = 0

Factor a trinomial.
-3((2 + x)(1 + x)) = 0

Ignore the factor -3.

Subproblem 1

Set the factor '(2 + x)' equal to zero and attempt to solve: Simplifying 2 + x = 0 Solving 2 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Subproblem 2

Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1

Solution

x = {-2, -1}

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